Was planning to work on this during the weekend but....
Ta Daa!
in any corner,
*
3dc cluster
chain 2
3dc cluster
chain 2
3dc cluster
chain 3
1dc in second loop (skip first loop)
chain 3
1dc in next loop
chain 3
1hdc in 2chain loop after 1st 3dc cluster
chain 2
sc in next 2chain space
chain 2
sc in next 2chain space
chain 2
1hdc in next 2 chain space before last 3dc cluster
chain 3
1dc in next loop
chain 3
1 dc in next loop
chain 3
skip last loop before next corner
**
repeat * to ** to finish all corners, join with ss into top of first 3dc cluster
Last row, chain 1, sc in same space, chain3 at corner, sc all round to complete.
Thank you Jo for solving my problem!